r^2+12r-160=0

Solution for r^2+12r-160=0 equation:

Simplifying
r2 + 12r + -160 = 0

Reorder the terms:
-160 + 12r + r2 = 0

Solving
-160 + 12r + r2 = 0

Solving for variable 'r'.

Factor a trinomial.
(-20 + -1r)(8 + -1r) = 0

Subproblem 1
Set the factor '(-20 + -1r)' equal to zero and attempt to solve:

Simplifying
-20 + -1r = 0

Solving
-20 + -1r = 0

Move all terms containing r to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + -1r = 0 + 20

Combine like terms: -20 + 20 = 0
0 + -1r = 0 + 20
-1r = 0 + 20

Combine like terms: 0 + 20 = 20
-1r = 20

Divide each side by '-1'.
r = -20

Simplifying
r = -20
Subproblem 2
Set the factor '(8 + -1r)' equal to zero and attempt to solve:

Simplifying
8 + -1r = 0

Solving
8 + -1r = 0

Move all terms containing r to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1r = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1r = 0 + -8
-1r = 0 + -8

Combine like terms: 0 + -8 = -8
-1r = -8

Divide each side by '-1'.
r = 8

Simplifying
r = 8
Solution
r = {-20, 8}